Question

$Calculati:$:

$a) (-9*7+4^3)^6+(-2^2)^3:(-2)^5+6^2:(-5*3^2+3^2*2^2);\\ b) -9:(-63+2*3^3)+(-8^3)^3:(-2^8)^3-(-98+2^5*3);$

Answer 1

Răspuns:

Explicație pas cu pas:

a)  

( - 9 x 7 + 4³ )⁶ + ( - 2²)³ : ( -2)⁵ + 6² : ( - 5x3² + 3²x2²) = - 5

= ( - 63 + 64 )⁶ + ( - 2)⁶⁻⁵ + 36 : ( - 45 + 9 x 4) =

= 1⁶ + ( - 2)¹ + 36 : ( - 45 + 36) =

= 1 - 2 + 36 : ( - 9) =

= - 1 - 4 =

= - 5

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b)

- 9 : ( - 63 + 2 x 3³) + (-8³)³: ( -2⁸)³ - ( - 98 + 2⁵ x 3 ) = - 5

= - 9 : ( - 63 + 2 x 27 ) + ( - 2³ˣ³)³ : ( -2)⁸ˣ³ - (-98 +32x3)=

= - 9 : ( - 63 + 54 ) + ( - 2)²⁷⁻²⁴ - ( - 98 + 96) =

= - 9 : ( - 9 ) + ( - 2 )³ - ( - 2 ) =

= 1 - 8 + 2 =

= - 7 + 2 =

= - 5

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daca ai - 9², atunci rezultatul este:

= - 81 : ( - 9 ) + ( - 2 )³ - ( - 2 ) = 3

= 9 - 8 + 2 =

= 1 + 2 =

= 3