Question

$E(x)= ( \frac{x-2}{x ^2 -4} * \frac{5x+10}{x-3} +1) * \frac{x-3}{x+2}$

x este  nr. real, x≠ -2, x≠2, x≠ 3. Aratati ca E(x) =1

Answer 1

Sper ca intelegi... am folosit formula a^2-b^2=(a-b)(a+b)