Question

$E(x)= \frac{x^3+2x^2-3x-6}{x^2-4}$
Aratati ca [tex]E(x)= \frac{x^2-3}{x+2}
[/tex]

Answer 1

E(x)=[x²(x+2)-3(x+2)]/[(x-2)(x+2)
E(x)=[(x+2)(x²-3)]/[(x-2)(x+2)] simplificam cu x+2
E(x)=(x²-3)/(x+2)

Answer 2

E(x)=$\frac{x^{2} (x+2)-3(x+2)}{(x-2)(x+2)}$
E(x)=$\frac{(x+2)( x^{2} -3)}{(x+2)(x-2)}$
E(x)=$\frac{x^{2}-3 }{x-2}$