Question

∞[tex] \frac{12}{25} : \frac{4}{75}

2 ^{n} * 3^{m+1}/5^{P+2} : 2 ^{n+2} * 3^{m+1}/5 [/tex]

Answer 1

$\frac{12}{25} : \frac{4}{75} = \frac{12}{25} * \frac{75}{4} = \frac{3}{1} * \frac{3}{1} =9$
12=3*4
75=3*25

$\frac{ 2^{n}* 3^{m+1} }{ 5^{P+2} } : \frac{ 2^{n+2}* 3^{m+1} }{5} = \frac{ 2^{n}* 3^{m+1} }{ 5^{P+2} } *\frac{5 }{2^{n+2}* 3^{m+1}} = \frac{1}{ 5^{P+1}* 2^{2} }$
$2^{n+2}= 2^{n}* 2^{2}$
$5^{P+2}= 5^{P+1}*5$