Question

$\frac{2 - 3x}{ {x}^{2} - x} + \frac{2}{x - 1} + \frac{5}{3x}$
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Answer 1

Răspuns:

$\dfrac{2-3x}{x^{2}-x}+\dfrac{2}{x-1}+\dfrac{5}{3x}= \dfrac{^{3)}2-3x}{x(x-1)}+\dfrac{^{3x)}2}{x-1}+\dfrac{^{x-1)}5}{3x}= \dfrac{3(2-3x)}{3x(x-1)}+ \dfrac{3x*2}{3x(x-1)} +\dfrac{5(x-1)}{3x(x-1)}=\dfrac{6-9x+6x+5x-5}{3x(x-1)}=\dfrac{2x+1}{3x(x-1)}$

Explicație pas cu pas: