Question

$\frac{6x-3}{6}$-$\frac{2x}{6}$=$\frac{x+3}{6}$

Answer 1

6x-3-2x=x+3
-3-3=6x+2x+x
6=8x
x=$\frac{6}{8}$ =$\frac{3}{4}$
Cred ca asa se rezolva, nu mai tin minte exact.

Answer 2

[tex]\frac{6x-3}{6}-\frac{2x}{6}=\frac{x+3}{6} |*6\\ 6x-3-2x=x+3\\ 4x-3=x+3\\ 3x=6=\ \textgreater \ x=2[/tex]