Question

$\frac{x}{x {}^{2} - 6x + 9 } \div ( \frac{1}{3 + x} - \frac{1}{3 - x} \frac{3x}{x {}^{2} - 9 } ) = \frac{3 + x}{3 - x}$
trebuie sa dovedeasca

Answer 1

Am atasat rezolvarea!