Question

$\int\limits {\frac{1}{x-1} } \, dx$

Answer 1

∫ 1/(x-1) dx= ln(x-1) +C

As simple as that.

Answer 2

$\int\limits {\frac{1}{x-1} } \, dx = ln(x-1) + c , pentru ca [ln(x-1)]'= \int\limits {\frac{1}{x-1} } \, dx$