Question

${\sqrt{1 \frac{3}{36} }* \sqrt{1 \frac{10}{39} }+ \frac{ \sqrt{48} } \sqrt{3} }=$

Answer 1

√39/36 × √ 49/39 +√3×√16/√3=
7/6+4=(7+24)/6=31/6 = 5 intregi si 1/6

Answer 2

= √(39/36 ) × √(49/39) + √48 /√3 = √(49/36) + 4√3 / √3 = 7/6 + 4 = 31/6 = 5 si 1/6