Question

$( \sqrt{3}+ \sqrt{6}) ^{2} -( \sqrt{2} - \sqrt{3}) ^{2} =$

Answer 1

o sa i iau pe bucati:
(r3+r6)^2=
3+2r18+6=
9+6r2

(r2-r3)^2=
2-2r6+3=
5-2r6

9+6r2-5+2r6=
4+6r2+2r6=
2(2+3r2+r6).

r= radical

Answer 2

=3+6+2rad18-2-3+2rad6=9+6rad2-5+2rad6=4+6rad2+2rad6