Question

$\sqrt[5]{ 2^{10} *3 ^{-5} }$

Answer 1

a la puterea -n = 1/a la puterea n

primul termen de sub radical este 2^10=1024

al doilea termen de sub radical este 3^-5=1/3^5=1/243

sub radical avem 1024*1/243=4.21

radical de ordin 5 din 4.21 = 1.33308063 

Answer 2

$\sqrt[5]{ 2^{10}*3^{-5} } = \sqrt[5]{ (2^2)^{5} }* \sqrt[5]{ (\frac{1}{3})^5 } =2^2* \frac{1}{3} = \frac{4}{3}=1,(3)$