Question

$\sqrt[6-x]{2x+1} = \sqrt[x-1]{{2}x^{2}-5 }$

Answer 1

x∈N* si

6-x≥2...4≥x

x-1≥2..x≥3

x∈{3;4}

pt x=3

∛7=∛13 fals

pt x=4

√9=∛27...3=3 adevarat

x=4

frumusel, exercitiul!