Question

$x^{2} +2mx+m^{2}$-1=0
Aratati ca ecuatia are solutii distincte

Answer 1

[tex]\triangle=b^2-4ac=(2m)^2-4(m^2-1)\\ \triangle=4m^2-4m^2+4\\ \triangle=4>0[/tex]
Cand o ecuatie de gradul doi are $\triangle>0$, stim ca va avea doua radacini reale distincte.