Question

${x}^{2} - 5x+4 = 0$

Answer 1

x^2-5x+4=0

/\=b^2-4ac=>/\=25-16=>/\=9

X1=(5+3)/2=>X1=4

X2=(5-3)/2=>X2=1

Answer 2

${x}^{2} - 5x + 4 = 0$

${x}^{2} - 4x - x + 4 = 0$

$x(x - 4) - (x - 4) = 0$

$(x - 4)(x - 1) = 0$

$x - 4 = 0 = > x = 4$

$x - 1 = 0 = > x = 1$