Question

$x^{2}$+2x+1=3+2$\sqrt{2}$

Answer 1

[tex]x^2+2x+1=3+2\sqrt{2}\\ (x+1)^2=(\sqrt{2}+1)^2\\ x+1=\sqrt{2}+1=\ \textgreater \ x=\sqrt{2}\\ x+1=-\sqrt{2}-1=\ \textgreater \ x=-\sqrt{2}-2[/tex]