Question

$( x^{2} -x +2) ^{2} + x^{2} ( - x^{2} +2x-5)$

Answer 1

[tex](x^2-x+2)^2+x^2(-x^2+2x-5)=\\ =(x^2-x+2)\cdot (x^2-x+2)+x^2(-x^2+2x-5)=\\ =x^4-x^3+2x^2-x^3+x^2-2x+2x^2-2x+4-x^4+2x^3-5x^2=\\ =-4x+4[/tex]