Question

Transformati in fractii ordinare ireductibile:1,(2);1,(51);0,(27)15,(105);0,(123)

Answer 1

[tex]1,(2) = 1 \frac{2}{9}= \frac{1*9+2}{9}= \frac{11}{9} \\ 1,(51) = 1 \frac{51}{99} = \frac{1*99+51}{99}= \frac{150}{99} \\ 0,(27)= 0 \frac{27}{99} = \frac{0*99+27}{99} = \frac{27}{99} \\ 15,(151) = 15 \frac{151}{999}= \frac{15*999+151}{999}= \frac{15136}{999} \\ 0,(123) = 0 \frac{123}{999} = \frac{0*999+123}{999} = \frac{123}{999} [/tex]