Question

Trei copii au impreuna 20 de nuci .Al doilea are de trei ori mai multe nuci decat primul . Cate nuci are fiecare copil calculand toate variantele stiind ca fiecare copil are cel putin o nuca .

Answer 1

a=nr nuci copil 1
b=3a =nr nuci copil 2
c=nr nuci copil 3
a+b+c=20 nuci
a+3a+c=20
4a+c=20
20-c = multiplu de 4
solutia 1
c=4nuci
4a+4=20nuci
a=4nuci
b=12nuci

solutia 2
c=8nuci
4a+8=20nuci
4a=12nuci
a=3nuci
b=9nuci

solutia 3
c=12nuci
4a+12=20nuci
4a=8nuci
a=2nuci
b=6nuci

solutia 4
c=16nuci
4a+16=20nuci
4a=4nuci
a=1nuci
b=3nuci