Question

Trei pese de metal. Cintaresc impreuna 155kg prima piesa este cu 28 kg mai grea decit a doua. Iar. A treia cu 22 kg mai grea decit a doua cit cintareate fiecare piesa?

Answer 1

a+b+c=155kg
a=b+28
c=b+22
acum inlocuim in relatia data
b+28+b+b+22=155kg
3b+28+22=155kg
3b+50=155kg
3b=155-50
3b=105
b=105:3
b=35kg

a+35+35+22=155kg
a+70+22=155kg
a+92=155kg
a=155-92
a=63kg

63+35+c=155kg
98+c=155kg
c=155-98
c=57kg

63+35+57=
98+57=155kg