Question

Trei-ul, vă rog frumos!!!

Answer 1

{x, y, z} i.p {2, 4, 8}=>

=>$\frac{x}{\frac{1}{2} }$=$\frac{y}{\frac{1}{4} }$=$\frac{z}{\frac{1}{8} }$=k=>x=$\frac{1}{2}$k; y=$\frac{1}{4}$k; z=$\frac{1}{8}$k

x+y+z=14=>

=>$\frac{1}{2}$k+$\frac{1}{4}$k+$\frac{1}{8}$k=14

aducem la acelasi numitor, deci:

$\frac{8k+4k+2k}{16}$=14

14k=14·16=>

=>k=$\frac{14x16}{14}$

k=16

de aici calculam x, y, z

x=$\frac{1}{2}$·16=>x=8

y=$\frac{1}{4}$·16=>y=4

z=$\frac{1}{8}$·16=>z=2