Question

Un biciclist a parcurs 331 km in trei zile astfel: in a doua zi a parcurs cu 27 km mai mult decat in prima zi si cu 19 km mai putin decat in a treia zi. Ce distanta a parcurs in fiecare zi?

Answer 1

I ZI =X KM
A II-A ZI = 27+X
A III-A ZI =27+X+19
DECI, X+27+X+27+X+19=331
3X+54+19=331
3X=331-73
3X=258,
X=86
DECI,
in prima zi =86 km
a doua zi = 86+27=113 km
a treia zi =113+19=132 km

Answer 2

a+b+c=331km
a=b-27....=>b=a+27
b=c-19....=>c=b+19....=>c=a+27+19
--------------------------------------------------
a=? b=? c=?

a+a+27+a+27+19=331
3a+27+27+19=331
3a+73=331
3a=331-73
3a=258
a=258:3
a=86km

b=86+27
b=113km

c=113+19
c=132

86km+113km+132km=331km