Question

Un biciclist parcurge distanta de 220 km.In prima zi a parcurs 2 supra 5 din distanta,a doua zi 1 supra 4 din rest,iar a treia zi restul distantei. repede va rog

Answer 1

$\frac{2}{5} 220=220:5*2= 88 km in prima zi$
$220-88=132 rest$
$\frac{1}{4} 132=132:4=33 km a doua zi$
$220-(88+33)=99 km a treia zi$

Answer 2

Δd=220km;
prima zi⇒2/5 ·220⇒2·220/5⇒2·44⇒88[km];
⇒au ramas 220km-88km⇒132km;
a doua zi⇒1/4 ·132⇒132/4⇒33[km];
⇒au ramas 132km-33km⇒99[km];
⇒a treia zi 99km;