Question

Un biciclist parcurge zilnic cu 10 km mai mult decat in ziua precedenta.In patru zile consecutive a parcurs 120 km.Aflati cati kilometri a parcurs in fiecare zi.

Answer 1

a+(a+10)+(a+10×2)+(a+10×3)=120

4a+60=120

4a=120-60

4a=60⇒a=15

a=15  km parcursi in prima zi

15+10=25 km parcursi in a doua zi

25+10= 35 km parcursi in a treia zi

35+10=45  km parcursi in  a patra zi

verificare  15+25+35+45=120⇒120=120 km

Answer 2

..


I — prima zi

II — a doua zi

III — a treia zi

IV — a patra zi




I + I + 10 + I + 20 + I + 30 = 120 = >


4I = 120 — 60 = >


4l = 60 =>


I = 60 : 4 = >


I = 15 km



II = 15 + 10

II = 25 km



III = 15 + 10 + 10

III = 25 + 10

III = 35 km



IV = 15 + 10 + 10 + 10

IV = 25 + 10 + 10

IV = 35 + 10

IV = 45 km