Question

un calator parcurge o distanta in 3 zile.In prima zi parcurge 60% din drum a doua zi 25% si in ultima zi 3 km.Cati km a parcurs in 3 zile

Answer 1

100-(60+25)=100-85=15
Deci 15% este egal cu 3 km
15:3=5 % un km
100÷5=20
20×1=20 km

Answer 2

x=distanta parcursa in cele trei zile
x=60x/100+25x/100+3=6x/10+x/4+3
20x=12x+5x+60
3x=60,x=20 km