Question

Un medicament pentru ulcer gastric contine 2,6 g Al(OH)3 in 100 ml. Ce volum de HCL 0,1 M poate neutraliza acest medicament?

Answer 1

Al(OH)3 + 3 HCl => AlCl3 + 3H2O

m Al(OH)3 = 2.6g => n Al(OH)3 = 2.6 g/ 78 (g/mol) = 0.033 mol Al(OH)3

1 mol Al(OH)3 .............. 3 mol HCl
0.033 mol Al(OH)3 ........x mol HCl 
x= 0.033 x 3= 0.099 ~ 0.1 mol HCl
C= n/V => V HCl = n/C = 0.1/0.1 = 1L solutie HCl 0.1 M