Question

Un numar este cu 36 mai mare decat altul.Impartind suma celor doua numere la diferenta lor obtinem catul 35 si restul 34.Determinati cele doua numere.Va multumesc .

Answer 1

x=36+y

(x+y):(x-y)=35 rest 34

(36+y+y):(36+y-y)=35 rest 34
(36+2y):36=35 rest 34
36+2y=36inmultit cu 35 +34
36+2y=1294
2y=1258
y=629

x=629+36
x=665

Answer 2

(a+36)+b=S
a-b= r
S:r=35 rest 34
---------------------
a=> b=?

(a+36)+b-a+b=r
r=36

S:36=35 rest 34
36*35+34=1294
S=1294
 
a+b=S-36
a+b=1294-36
a+b=1258
1258:2=629
b=629
a=629+36
a=665

a+b=S
665+629=1294
a-b=r
665-629=36
1294:36=35 rest 34

a=665
b=629
S=1294
r=36