Question

un trapez are inaltimea de 8 cm are baza dea are 14cm si baza mica de 6cm. linia mijlocie atrapezului are lungimea egala cu

Answer 1

   
[tex]\displaystyle \\ \text{Linia mijlocie a trapezului } = \frac{\text{Baza mare + Baza mica}}{2} \\ \\ L_m = \frac{B + b}{2} = \frac{14+6}{2} =\frac{20}{2} = \boxed{10~cm}[/tex]

Answer 2

$A=\frac{(B+b)*h}{2} = \\ \\ A= \frac{(14+6)*8}{2} =80 cm^{2} \\ \\ A= l_{m}*h \\ \\ l_{m} =A:h \\ \\ l_{m} =80:8 \\ \\ l_{m} =10cm$