Question

URGENT!
1. f:rR--> R,f(x)=$\frac{3}{5 } }$x -4    f(5)+f(10)
2.f:rR--> R,f(x)=1-2x,A(-2,5) ∈ Gf?
3.A(2,6)∈ Gf,f:{2,3,4}--> R,f(x)=ax+2 atunci =..

Answer 1

1) f(5)=3/5 x 5 -4=-1
f(10)= 3/5 x 10 - 4 = 2
f(5) + f(10) = -1 +2=1
2)  f(x)= 1-2x      A(-2,5)
f(-2)= 1-2(-2)= 1+4=5  deci A∈graficului
3)  f(x)= ax+2
f(2)= 2a+2
f(2)=6  deci 2a+2=6  2a=4  a=2