Question

URGENT!!!


300 de grame de calciu de puritate 80% reactioneaza cu azotul. Ce cantitate (in moli si in grame) de produs de reactie se va obtine ?

Answer 1

Răspuns:

p=m pur/m impur*100 => mpur=80×300/100=240g Ca

calculam in grame masa de Ca3N2

3Ca + N2 → Ca3N2

MCa=40g/mol

MCa3N2=3×40+2×14=148g/mol

80g Ca...........................148g Ca3N2

240g0g Ca........................x

x=240×148/80=444gCa3N2

calculam in moli masa de Ca3N2

MCa=40g/mol

m=240g

n=240/80=3moliCa

3moli               1mol

3Ca   +   N2 → Ca3N2

3moli               ymol

y=3×1/3=1molCa3N2

Explicație: