Question

URGENT!!!!!!!!!!!!!!!!!!​

Answer 1

Răspuns:

a) 10 FeSO4 + 2 KMnO4 + 8 H2SO4 → 5 Fe2(SO4)3 + 2 MnSO4 + K2SO4 + 8 H2O

2 MnVII + 10 e- → 2 MnII (reducere)

10 FeII - 10 e- → 10 FeIII (oxidare)

b) 4 Al  + 3 O2 → 2 Al2O3

4 Al0 - 12 e- → 4 AlIII (oxidare)

6 O0 + 12 e- → 6 O-II (reducere)

c)  2 MnO2 + 2 H2SO4  + → 2 MnSO4  +  O2 +2 H2O

2 MnIV + 4 e- → 2 MnII (reducere)

2 O-II - 4 e- → 2 O0 (oxidare)

d) 3 Cu  + 8 HNO3 → 3 Cu(NO3)2 + 2 NO + 4 H2O

3 Cu0 - 6 e- → 3 CuII (oxidare)

2 NV + 6 e- → 2 NII (reducere)

e) K2Cr2O7 + 6 HI + 4 H2SO4 → K2SO4 + Cr2(SO4)3 + 3 I2 + 7 H2O

6 I-I - 6 e- → 6 I0 (oxidare)

2 CrVI + 6 e- → 2 CrIII (reducere)

f) 4 Na2SO3  → Na2S  + 3 Na2SO4

SIV + 6 e- → S-II (reducere)

3 SIV - 6 e- → 3 SVI (oxidare)

g) 3H2S + 2HNO3 = 3S + 2NO +4H2O

S 2- -2e → S0|x3 (oxidare )

N +5 +3e → N +2|x2 (reducere )

h) 2 KMnO4 + 6 HCl  + 5 H2S → 2 KCl  + 2 MnCl2 + 5 S  + 8 H2O

2 MnVII + 10 e- → 2 MnII (reducere)

5 S-II - 10 e- → 5 S0 (oxidare)

Explicație: