Question

Urgent ca nu imi d-au seama :


calculati numarul de moli corespunzator urmatoarelor cantitati de substanta
a) 588gH2SO4 c)67,12x10la22 molecule de CO2
b)156,8 Litri (c.m) N2 d)6l O2 la 30 de grade si 6 atmosfere

Answer 1

stim ca numarul de moli( niu ) este egal cu m/M, unde m=masa(in grame) si M=masa molara(g/mol)
a)
niu=m/M
=>niu=588/98=6 mol
M H2SO4= 2+32+64=98 g/mol

b)156,8 L
niu= V/Vm
unde V=volum si Vm=volum molar( o constanta folosita in conditii normale , egala cu 22,4 )
=> niu= 156,8/22,4
niu=7 mol

c)67,12•10^22 molecule
niu=N/N A
unde N=nr de particule , molecule , atomi si N indice A= numarul lui Avogadro( 6,022•10^23 )
=> niu = 67,12•10^22 / 6,022•10^23
niu=11,14•10^-1=1,114 mol

d)V=6L O2
T=30+273=303 k (transformam in grade kelvin)
p=6 atm
aplicam ecuatia de stare :
p•V=niu•R•T
=>6•6=niu•0,082•303
=>niu=36/24,846
=>niu=1,448 mol O2

Sper ca te am ajutat!