Question

URGENT!!!! Calculati: (2a/a²-4 -2/a-2 + 1/a+2) :a-6/4(a+2)......Vaaa rooog dau coronita..!..Multumesc anticipat!

Answer 1

Conditia de existenta a∈R/{-2,2}
[2a/(a-2)(a+2) -2/(a-2) +1/(a+2)]:(a-6)/4(a+2)=
numitor comun la prima paranteza (a-2)(a+2)
[2a-2(a+2)+(a-2)]/(a-2)(a+2) :(a-6)/4(a+2)=
(2a-2a-4+a-2)/(a-2)(a+2):(a-6)/4(a+2)=
(a-6)/a-2)(a+2) · 4(a+2)/(a-6)=
simplificand
=4/(a-2)