Question

URGENT Cate g Al de p=81% reactioneaza cu 200 g HCL de c=3,65? Multumesc

Answer 1

C=md/ms*100=>md=C*ms/100=3,65*200/100=7,3g HCl

MHCl=AH+ACl=1+35,5=36,5g/mol

MAl=27g/mol

2Al + 6HCl => AlCl3 + 3H2

2*27g Al................6*36,5g HCl
xg Al.....................7,3g HCl

x=7,3*54/6*36,5=1,8g Al pur

puritatea = masa pura/masa impura*100 => masa impura= masa pura*100/puritate = 1,8*100/81 = Calculeaza !!