Question

URGENT DAU CORONITA <3

introduceti intregul in fractie


2 din 3/5

12 din 1/3


101 din 3/17


scoateti intregii din fractie

8/3


37/11


400/103

Answer 1

$2\frac{3}{5} = \frac{2*5+3}{5} = \frac{13}{5} \\ \\ 12 \frac{1}{3} = \frac{12*3+1}{3} = \frac{37}{3} \\ \\ 101 \frac{3}{17} = \frac{101*17+3}{17}= \frac{1720}{17} \\ \\ \\ \frac{8}{3} =2 \frac{2}{3} \\ \\ \frac{37}{11} =3 \frac{4}{11} \\ \\ \frac{400}{103}=3 \frac{97}{103}$