Question

Dau coroana
Ajutor!!!

Answer 1

Se aduce la numitor comun de ambele parti ale egalitatii(12)
(12·2-6·1+4·1-3·1+1)=x(1·12-1·6-1·4+1·3)
24-6+4-3+1=x(12-6-4+3)
20=5x =>x=4

Answer 2

$2- \frac{1}{2}+ \frac{1}{3}- \frac{1}{4} + \frac{1}{12} =x(1- \frac{1}{2} - \frac{1}{3}+ \frac{1}{4} ) \\ \\ 2- \frac{1}{2}+ \frac{1}{3}- \frac{1}{4} + \frac{1}{12} = \frac{2*12-1*6+1*4-1*3+1}{12} = \\ \\ =\frac{20}{12} = \frac{5}{3} \\ \\ (1- \frac{1}{2} - \frac{1}{3}+ \frac{1}{4} )= \frac{(12-6-4+3)}{12} = \frac{5}{12} \\ \\ \frac{5}{3}=x( \frac{5}{12} ) \\ \\ x= \frac{12*5}{5*3} \\ \\ x=4$