Question

Urgent!
Determinatei elementele urmatoarelor multimi:
C= {x ∈ N | $\frac{3x-2}{x+4}$ ∈ N

D={ x ∈ N | $\frac4x+3}{5x-1}$ } ∈ N

Answer 1

[tex]1)C=\{x\in N| \frac{3x-2}{x+4}\in N\} \\ x+4|3x-2 \\ x+4|x+4 =\ \textgreater \ x+4|3x+12 \\ Deci \\ x+4|(3x+12)-(3x-2) \\ x+4|14 \\ x+4\in\{1,2,7,14\} \\ x\in\{-3,-2,3,10\}Dar x\in N=\ \textgreater \ x\in\{3,10\} \\ \\ [/tex]

La a doua multime,din forma scrisa de tine, trebuie ca x sa fie divizor al lui 4,
deci poate lua valorile {1,2,4}