Question

Urgent!
metoda mersului invers - cls. 5

Answer 1

2008 : { [ ( a × 7 ) : 3 + 18 ] × 2 - 9 } + 119 = 127

2008 : { [ ( a × 7 ) : 3 + 18 ] × 2 - 9 } = 127 - 119

2008 : { [ ( a × 7 ) : 3 + 18 ] × 2 - 9 } = 8

[ ( a × 7 ) : 3 + 18 ] × 2 - 9 = 2008 : 8

[ ( a × 7 ) : 3 + 18 ] × 2 - 9 = 251

[ ( a × 7 ) : 3 + 18 ] × 2 = 251 + 9

[ ( a × 7 ) : 3 + 18 ] × 2 = 260

( a × 7 ) : 3 + 18 = 260 : 2

( a × 7 ) : 3 + 18 = 130

( a × 7 ) : 3 = 130 - 18

( a × 7 ) : 3 = 112

a × 7 = 112 × 3

a × 7 = 336

a = 336 : 7

a = 48 → numarul, aflat prin metoda mersului invers