Question

URGENT! prin reactia 2,8g metal divalent cu soluție de acid sulfuric 36,5% se formeaza 0,05 moli H2 a)masa atomica a metalului b)sa se calc cant. solutie acid sulfuric 36,5% consumat

Answer 1

Fie Me metalul divalent


AMe g 98 g 1 mol
Me + H2SO4 -> MeSO4 + H2
2.8g md 0.05 mol

AMe=2,8*1/0.05
AMe=56g

MH2SO4=2*1+32+4*16=98g/mol
md=0.05*98/1
md=4,9g
c=36,5%
c/100=md/ms => ms=100md/c
ms=100*4,9/36,5
ms=13,42g sol H2SO4