Question

urgent va rog mult dau coroana

Answer 1

a)$\frac{y+2}{2y+1}$-$\frac{2y-3}{2y+1}$=$\frac{y+2-2y+3}{2y+1}$=$\frac{-y+5}{2y+1}$


b)$\frac{x+1}{3x}$+$\frac{2-X}{y4x}$=$\frac{4x^2+4x+6x-3x^2}{12x}$=$\frac{x^2+10}{12x}$=$\frac{x(x+10)}{12x}$=$\frac{x+10}{12}$