Question

URGENT VA ROOG!!
In triunghiul ABC consideram punctul E ∈ (MN) si construim EF║BC,F ∈ (AC).Daca:
a)AE=2 cm,EB=4 cm si AF=3 cm,aflati FC
b)EB=3 cm,AF=3 cm si FC=9 cm,aflati AE
c)AE=5 cm,AB=20 cm si AF=10 cm,aflati AC
d)AB=18 cm,AF=7 cm si AC=21 cm,aflati AE
e)EB=2 cm,AB=10 cm si AC= 15 cm,aflati FC
f)AC=25 cm,FC=15 cm si EB=9 cm,aflati AB

Answer 1

ΔAEF≈ΔABC⇒T.Thals⇒AE/AB = AF/AC
dar AB=AE+EB si AC=AF+FC, inlocuim in prima relatie
AE/ AE+EB = AF/ AF+FC
2/6=3/ 3+FC
3+FC=9
FC=6

Se rezolva identic si celelalte puncte. Succes!