Question

Urgent!Valoare integralei. Poza atasata.

Answer 1

$\displaystyle \int\limits^1_0 {(|x-1|+1})dx= \int\limits^1_0 (-x+1+1)dx= \int\limits^1_0 (-x+2)dx= -\int\limits^1_0 xdx+ \int\limits^1_0 2dx=\\\\=-\frac{x^2}{2}\Bigg|_0^1+2x\Bigg|_0^1=-\Bigg(\frac{1^2}{2} -\frac{0^2}{2} \Bigg)+2(1-0)=-\frac{1}{2}+2=\frac{-1+4}{2} =\frac{3}{2}$