Question

utilizând Formula
1+2+3+...+n=(1+n)×n÷2 calculati ;
2+4+6+...+200=​ dau coroana!!

Answer 1

2+4+6+...200=

2(1+2+3+...100)=

2[(1+100)×100:2]=

2(101×50)=

2×5050=

10100