Question

(V7-5)+(3-V7)+(-2)=?

Answer 1

$(\sqrt{7} -5)+(3- \sqrt{7}) +(-2)=\\ ( ~ \sqrt{7} cu - \sqrt{7}~se ~reduc~adica~le ~taiem~si ~rezulta:)\\ =-5+3+(-2)\\ =-4$

Answer 2

(7v-5)+(3-7v)+(-2)=
7v-5+3-7v-2
=se reduc 7v cu -7v
=-5+3-2
=-2-2
=-4