Question

Va implor ajutati-ma!
radical 6 x (3 radical 5 - 2 radical 5) - radical 2 x radical 15= ?
2 x (radical 12 - radical 3) + (radical 27 - radical 48) x 3= ?
6 radical 7 + 3 ( radical 3 - 2 radical 7) = ?
3 x (2 radical 7 - 3 radical 3) - radical 252 =?
( x este ori)

Answer 1

a) √6*√5-2√15=√30-2√15
b) 2*(2√3-√3)+(3√3-4√3)*3=
  =2*√3+(-√3)*3=
  =2√3-3√3=-√3
c)6√7+3√3-6√7=3√3
d)6√7-9√3-6√7=-9√3

Answer 2

$1).\sqrt{6} (3 \sqrt{5} -2 \sqrt{5} )- \sqrt{2} * \sqrt{15} = \sqrt{6} * \sqrt{5} - \sqrt{30} = \sqrt{30} - \sqrt{30} =0 \\ 2).2( \sqrt{12} - \sqrt{3} )+( \sqrt{27} - \sqrt{48} )*3= \\ =2(2 \sqrt{3} - \sqrt{3} )+(3 \sqrt{3} -4 \sqrt{3} )*3=2* \sqrt{3} - \sqrt{3} *3= \\ =2 \sqrt{3} -3 \sqrt{3} =- \sqrt{3}$
$3).6 \sqrt{7} +3( \sqrt{3} -2 \sqrt{7} )=6 \sqrt{7} +3 \sqrt{3} -6 \sqrt{7} =3 \sqrt{3} \\ 4).3(2 \sqrt{7} -3 \sqrt{3} )- \sqrt{252} =6 \sqrt{7} -9 \sqrt{3} -6 \sqrt{7} =-9 \sqrt{3}$