Matematică, întrebare adresată de bibbia789, 8 ani în urmă

VA IMPLOR!!! AM NEVOIE URGENT ALEGETI ORICE SUBPUNCTE VRETI!!​

Anexe:

Răspunsuri la întrebare

Răspuns de mbc220861
0

Răspuns:

Explicație pas cu pas:

a) 1,2(6)/19-0,0(6)=(126-12)/(90·19)-6/90=114/(90·19)-(6·19)/(90·19)=

(114-114)/(90·19)=0/(90·19)=0

b) (24,2+4/5)/4,(54)=(242/10+8/10)/(454-4)/9=(250/10)/(450/99)=

(250/10)·(99/450)=(25·99)/(450)=99/18=11/2

c) [0,1(3)+0,0(5)]/5,(6)=(13-1)/90+5/90]/(56-5)/9=(12/90+5/90)/(51/9)=

(17/90)·(9/51)=(17·9)/(90·51)=17/(10·51)=1/(10·3)=1/30

d) [0,(27)+0,25]/(23/44)=[27/99+25/100]/(23/44)=[(2700+2475)/99·100]·44/23= (5175·44)/(99·100·23)=(5175·4)/(9·100·23)=

(207·4)/(9·4·23)=207/(9·23)=23/23=1

e) [0,4(6):14/3+0,4]:2,5=(42/90·3/14+4/10):25/10=(42·3/90·14+4/10)  ·10/25=

(1/10+4/10)·10/25=5/10·10/25=5·10/10·25=5/25=1/5

f) [0,(5)·1,35+1,2(7):46/12]:0,13/0,12=(5/9·135/100+115/90·12/46):13/100·(100/12)=(5·135/9·100+115·12/90·46):13/12=(135/9·20+23·12/18·46)·(12/13)=(15/20+23·2/3·46)·(12/13)=(3/4+1/3)·(12/13)=(9+4)/12·(12/13)=13/12·(12/13)=

13·12/12·13=1

g) [0,(2)·1,875+1,(27):7/22]:(0,53/0,12)=[2/9·1875/1000+126/99·22/7]:(53/100/12/100)=[2·75/(9·40)+126·2/9·7]:53/12=[75/9·20+4]·12/53=(5/12+48/12)·12/53=53/12·(12/53)=53·12/(12·53)=1

Alte întrebări interesante