Question

va rog ajuatima...
Substituiti astfel incat multimea solutiilor ecuatiei obtinute sa fie:
a)S ={1} b)S ={0} c)S ={-1} d)S =Ф
4x-3=3x+...

Answer 1

a)4x-3=3x+y
  S={1}⇒x=1 si 4·1-3=3·1+y=>1=3+y y=1-3=-2 ⇒4x-3=3x-2
b)4x-3=3x+y
 S ={0}⇒x=0si 4·0-3=3·0+y⇒-3=y⇒4x-3=3x-3
b)4x-3=3x+y
 S ={-1}⇒x=-1 si 4·(-1)-3=3·(-1)+y ⇒-7=-3+y ⇒y=-7+3=-4⇒4x-3=3x-4
b)4x-3=3x+y
 S ={Ф}⇒4x-3=3x+x ⇒4x-3=4x Fals⇒x=Ф

Answer 2

a)4x-3=3x+y
  S={1}⇒x=1 si 4·1-3=3·1+y=>1=3+y y=1-3=-2 ⇒4x-3=3x-2
b)4x-3=3x+y
 S ={0}⇒x=0si 4·0-3=3·0+y⇒-3=y⇒4x-3=3x-3
b)4x-3=3x+y
 S ={-1}⇒x=-1 si 4·(-1)-3=3·(-1)+y ⇒-7=-3+y ⇒y=-7+3=-4⇒4x-3=3x-4
b)4x-3=3x+y
 S ={Ф}⇒4x-3=3x+x ⇒4x-3=4x Fals⇒x=Ф
Sper sa iti fie de ajutor.