Question

va rog ajutati Ma!!!!!!!!!!!!!

Answer 1

[tex]S_A=-3-6-9-...-300=-3(1+2+3+...+100)\\ S_B=-4-8-12-...-400=-4(1+2+3+...+100)\\ \frac{S_A}{S_B}=\frac{-3(1+2+...+100)}{-4(1+2+..+100)}=\frac{3}{4}\\ (\frac{S_A}{S_B})^{-1}=\frac{S_B}{S_A}=\frac{4}{3}[/tex]