Question

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Answer 1

1.$\frac{1}{2} + \frac{1}{4} *(- \frac{2}{3}) = \frac{1}{2} - \frac{2}{12} = \frac{6}{12} - \frac{2}{12} = \frac{4}{12} = \frac{1}{3}$
2.A={ -3 ; √37;√100;0,(3);-$\sqrt{3* \frac{2}{9} }$}
 -3 ∈Q
√100∈Q
-$\sqrt{3* \frac{2}{9} }$∈Q
A∩Q = {-3;√100;-$\sqrt{3* \frac{2}{9} }$}
3.$(2-x)^{2}$ = $2^{2}$ - 4x + $x^{2}$
(5-x)(5+x)=$5^{2}$ - $x^{2}$
$(1+5x)^{2}$ = 1 + 10x + $(5x)^{2}$
4.$\sqrt{18}$÷$\sqrt{2]$-$\sqrt{9}$=$\sqrt{9}$-$\sqrt{9}$ = 0
5.$\frac{4- \sqrt{3}+4+ \sqrt{3} }{4}$ = $\frac{8}{4}$ = 2
6.Insuficiente detalii
7.A = 1024 cm^2 => l = $\sqrt{1024}$ => l = 32 => P = 32 * 4 = 128cm
8.nu stiu relatii metrice
9.AC = 10 cm ,BC = 8 cm => P = 10 cm *2 + 8 cm*2=36cm