Question

Va rog ajutati-ma cu acest exercitiu 19

Answer 1

[tex]a) \sqrt{3^2} \cdot \sqrt{25-16} =3\cdot 3=9\\ b) \sqrt{9+ \frac{81}{16} } = \sqrt{ \frac{225}{16} }= \frac{15}{4} \\ c)| \sqrt{2} -2|+ \sqrt{4} =2- \sqrt{2} +2=4- \sqrt{2} \\ d)|1- \sqrt{3} |- \sqrt{3} = \sqrt{3} -1- \sqrt{3} =-1\\ e) \sqrt{2-3 \sqrt{2}-3 \sqrt{2}+9 } = \sqrt{11-6 \sqrt{2} }=|3- \sqrt{2} |=3- \sqrt{2}[/tex]Scrie răspunsul tău aici