Matematică, întrebare adresată de alexandrumihai547, 9 ani în urmă

Va rog ajutati ma cu exercitiile (608:16-270:30).2-19.3= [(205:5+13.5):2-2.25]:3+1= 25-[300:10+2(725:5-29.5)-4.5]= 3[35+16.(230-19.12)]-[14.3+82.3-4.(2+4.5)] = [302+19.(68-8.6)]:2-2.17.10= 25.13+325:[178-17.(27.7-18.10= 1734-{214.2+2[196.4-39.3-896:(420.14-419.14)]}= {[(7.3-5)+2.6]:7+210:35}:10+9= [265-(50:25+2).65].2-(100:25+5=


dannadanielle: le-ai mai scris odata si acolo ai rezolvarea lor

Răspunsuri la întrebare

Răspuns de dannadanielle
1
(608÷16-270÷30)×2-19×3=
=(38-9)×2-57=
=2×38-2×9-57=76-18-57=1
[(205÷5+13×5)÷2-2×25]÷3+1=
=[(41+65)÷2-50]÷3+1=
=(106÷2-50)÷3+1=
=(53-50)÷3+1=3÷3+1=2
25-[300÷10+2(725÷5-29×5)-4×5]=
=25-[30+2(145-145)-20]=
=25-(30+0-20)=25-10=15
3[35+16(230-19×12)]-[14×3+82×3-4(2+4×5)]=
=3[35+16(230-228)]-(42+246-4×22)=
=3(35+16×2)-(42+246-88)=
=3(35+32)-200=3×67-200=201-200=1

[302+19×(68-6×8)]÷2-2×17×10=
=(302+19×20)÷2-340=
=(302+380)÷2-340=
=682÷2-340=341-340=1

25×13+325÷[178-17×(27×7-18×10)]×5=
=325+325÷[178-17×(189-180)]×5=
=325+325÷(178-17×9)×5=
=325+325÷(178-153)×5=325+325÷25×5=325+13×5=325+65=390

1734-{214×2+2[196×4-39×3-896÷(420×14-419×14)]}=
=1734-{428+2[784-117-896÷(5880-5866)]}=
=1734-[428+2(784-117-896÷14)]=
=1734-[428+2(784-117-64)]=
=1734-(428+2×603)=
1734-(428+1206)=1734-1634=100

{](7×3-5)+2×6]÷7+210÷35}÷10+9=
={[(21-5)+12]÷7+6}÷10+9=
=[(16+12)÷7+6]÷10+9=
=(28÷7+6)÷10+9=(4+6)÷10+9=10÷10+9=1+9=10

[265-(50÷25+2)×65]×2-(100÷25+5)=
=[265-(2+2)×65]×2-(4+5)=
=(265-4×65)×2-9=
=(265-260)×2-9=5×2-9=10-9=1

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